Posts  / #POST-233582
REDDIT

Best Advice for Stonks

Buy Low-Sell High

Calories in Calories out

get in early then leave earlier yer friends

Someone must lose for someone to gain.

But why can't we win?

Suppose your portfolio has value VPV\_PVP​ and return RPR\_PRP​. You add a hedge instrument with return RHR\_HRH​ and hedge weight hhh.

The hedged portfolio return is:

Rhedged=RP+hRHR\_{\\text{hedged}} = R\_P + hR\_HRhedged​=RP​+hRH​

Here:

* h>0h>0h>0: you are long the hedge instrument.
* h<0h<0h<0: you are short the hedge instrument.
* h=−1h=-1h=−1: the hedge has the same dollar size as the portfolio, but in the opposite direction.

The variance of the hedged portfolio is:

Var⁡(Rhedged)=σP2+h2σH2+2hCov⁡(RP,RH)\\operatorname{Var}(R\_{\\text{hedged}}) = \\sigma\_P\^2+h\^2\\sigma\_H\^2+2h\\operatorname{Cov}(R\_P,R\_H)Var(Rhedged​)=σP2​+h2σH2​+2hCov(RP​,RH​)

Because:

Cov⁡(RP,RH)=ρPHσPσH\\operatorname{Cov}(R\_P,R\_H)=\\rho\_{PH}\\sigma\_P\\sigma\_HCov(RP​,RH​)=ρPH​σP​σH​

we can write:

σhedged2=σP2+h2σH2+2hρPHσPσH\\sigma\_{\\text{hedged}}\^2 = \\sigma\_P\^2+h\^2\\sigma\_H\^2 +2h\\rho\_{PH}\\sigma\_P\\sigma\_Hσhedged2​=σP2​+h2σH2​+2hρPH​σP​σH​

To find the hedge ratio that minimizes variance, differentiate with respect to hhh:

∂σhedged2∂h=2hσH2+2Cov⁡(RP,RH)\\frac{\\partial \\sigma\_{\\text{hedged}}\^2}{\\partial h} = 2h\\sigma\_H\^2+2\\operatorname{Cov}(R\_P,R\_H)∂h∂σhedged2​​=2hσH2​+2Cov(RP​,RH​)

Set that equal to zero:

2hσH2+2Cov⁡(RP,RH)=02h\\sigma\_H\^2+2\\operatorname{Cov}(R\_P,R\_H)=02hσH2​+2Cov(RP​,RH​)=0

Therefore:

h∗=−Cov⁡(RP,RH)Var⁡(RH)\\boxed{ h\^\*=-\\frac{\\operatorname{Cov}(R\_P,R\_H)} {\\operatorname{Var}(R\_H)} }h∗=−Var(RH​)Cov(RP​,RH​)​​

Or:

h∗=−ρPHσPσH\\boxed{ h\^\*=-\\rho\_{PH}\\frac{\\sigma\_P}{\\sigma\_H} }h∗=−ρPH​σH​σP​​​

This is the **minimum-variance hedge ratio**.

# 2. Minimum-variance example

Assume:

VP=$1,000,000V\_P=\\$1,000,000VP​=$1,000,000

Portfolio volatility:

σP=24%\\sigma\_P=24\\%σP​=24%

Hedge volatility:

σH=18%\\sigma\_H=18\\%σH​=18%

Correlation:

ρPH=0.75\\rho\_{PH}=0.75ρPH​=0.75

The optimal hedge ratio is:

h∗=−(0.75)0.240.18h\^\* = -(0.75)\\frac{0.24}{0.18}h∗=−(0.75)0.180.24​ h∗=−1.00h\^\*=-1.00h∗=−1.00

Therefore, the mathematical model says to short approximately:

$1,000,000\\$1,000,000$1,000,000

of the hedge instrument.

The resulting variance is:

σhedged2=0.242+(−1)2(0.18)2+2(−1)(0.75)(0.24)(0.18)\\sigma\_{\\text{hedged}}\^2 = 0.24\^2+(-1)\^2(0.18)\^2 +2(-1)(0.75)(0.24)(0.18)σhedged2​=0.242+(−1)2(0.18)2+2(−1)(0.75)(0.24)(0.18) =0.0576+0.0324−0.0648= 0.0576+0.0324-0.0648=0.0576+0.0324−0.0648 =0.0252=0.0252=0.0252

Therefore:

σhedged=0.0252≈15.87%\\sigma\_{\\text{hedged}} = \\sqrt{0.0252} \\approx 15.87\\%σhedged​=0.0252​≈15.87%

The hedge reduces estimated annual volatility from:

24%→15.87%24\\%\\rightarrow15.87\\%24%→15.87%

It does not remove all risk because the correlation is only 0.750.750.75, not 1.001.001.00.

The remaining risk is called **basis risk** or **idiosyncratic risk**.